Tính A = 2 + 23 + 25 + 27 + ... + 22009.
Trả lời
Ta có:
A = 2 + 23 + 25 + 27 + ... + 22009
4A = 23 + 25 + 27 + ... + 22011
4A – A = (23 + 25 + 27 + ... + 22011) – (2 + 23 + 25 + 27 + ... + 22009)
3A = 22011 – 2
\(A = \frac{{{2^{2011}} - 2}}{3}\)
Vậy \(A = \frac{{{2^{2011}} - 2}}{3}\).