Tính tổng \(S = C_{2019}^1 + C_{2019}^2 + ... + C_{2019}^{2018}\).
Trả lời
Ta có: \(S = C_{2019}^1 + C_{2019}^2 + ... + C_{2019}^{2018}\)
\( \Rightarrow S + C_{2019}^0 + C_{2019}^{2019} = C_{2019}^0 + C_{2019}^1 + C_{2019}^2 + ... + C_{2019}^{2018} + C_{2019}^{2019}\)
⇔ S + 1 + 1 = (1 + 1)2019
⇔ S = 22019 – 2.